(2r-3)(r^2+2r-5)=

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Solution for (2r-3)(r^2+2r-5)= equation: 


Simplifying
(2r + -3)(r2 + 2r + -5) = 0

Reorder the terms:
(-3 + 2r)(r2 + 2r + -5) = 0

Reorder the terms:
(-3 + 2r)(-5 + 2r + r2) = 0

Multiply (-3 + 2r) * (-5 + 2r + r2)
(-3(-5 + 2r + r2) + 2r * (-5 + 2r + r2)) = 0
((-5 * -3 + 2r * -3 + r2 * -3) + 2r * (-5 + 2r + r2)) = 0
((15 + -6r + -3r2) + 2r * (-5 + 2r + r2)) = 0
(15 + -6r + -3r2 + (-5 * 2r + 2r * 2r + r2 * 2r)) = 0
(15 + -6r + -3r2 + (-10r + 4r2 + 2r3)) = 0

Reorder the terms:
(15 + -6r + -10r + -3r2 + 4r2 + 2r3) = 0

Combine like terms: -6r + -10r = -16r
(15 + -16r + -3r2 + 4r2 + 2r3) = 0

Combine like terms: -3r2 + 4r2 = 1r2
(15 + -16r + 1r2 + 2r3) = 0

Solving
15 + -16r + 1r2 + 2r3 = 0

Solving for variable 'r'.

The solution to this equation could not be determined.

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